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Histogram: Fix and simplify histogram_quantile
For conventional histograms, we need to gather all the individual bucket timeseries at a data point to do the quantile calculation. The code so far mirrored this behavior for the new native histograms. However, since a single data point contains all the buckets alreade, that's actually not needed. This PR simplifies the code while still detecting a mix of conventional and native histograms. The weird signature calculation for the conventional histograms is getting even weirder because of that. If this PR turns out to do the right thing, I will implement a proper fix for the signature calculation upstream. Signed-off-by: beorn7 <beorn@grafana.com>
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@ -989,8 +989,6 @@ type EvalNodeHelper struct {
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Dmn map[uint64]labels.Labels
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// funcHistogramQuantile for conventional histograms.
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signatureToMetricWithBuckets map[string]*metricWithBuckets
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// funcHistogramQuantile for the new histograms.
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signatureToMetricWithHistograms map[string]*metricWithHistograms
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// label_replace.
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regex *regexp.Regexp
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@ -869,7 +869,6 @@ func funcHistogramQuantile(vals []parser.Value, args parser.Expressions, enh *Ev
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q := vals[0].(Vector)[0].V
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inVec := vals[1].(Vector)
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sigf := signatureFunc(false, enh.lblBuf, labels.BucketLabel)
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ignoreSignature := make(map[string]bool) // For signatures having both new and old histograms.
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if enh.signatureToMetricWithBuckets == nil {
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enh.signatureToMetricWithBuckets = map[string]*metricWithBuckets{}
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@ -878,45 +877,19 @@ func funcHistogramQuantile(vals []parser.Value, args parser.Expressions, enh *Ev
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v.buckets = v.buckets[:0]
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}
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}
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if enh.signatureToMetricWithHistograms == nil {
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enh.signatureToMetricWithHistograms = map[string]*metricWithHistograms{}
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} else {
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for _, v := range enh.signatureToMetricWithHistograms {
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v.histogram = nil
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}
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}
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for _, el := range inVec {
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l := sigf(el.Metric)
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if ignoreSignature[l] {
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continue
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}
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if el.H != nil { // It's a histogram type.
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_, ok := enh.signatureToMetricWithBuckets[l]
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if ok {
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// This signature exists for both conventional
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// and new histograms, which is not supported.
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// TODO(beorn7): Issue a warning somehow.
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delete(enh.signatureToMetricWithBuckets, l)
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delete(enh.signatureToMetricWithHistograms, l)
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ignoreSignature[l] = true
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continue
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}
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var histogramSamples []Sample
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_, ok = enh.signatureToMetricWithHistograms[l]
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if ok {
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panic(errors.New("histogram_quantile: vector cannot contain metrics with the same labelset"))
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}
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el.Metric = labels.NewBuilder(el.Metric).
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Del(labels.BucketLabel, labels.MetricName).
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Labels()
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enh.signatureToMetricWithHistograms[l] = &metricWithHistograms{el.Metric, el.H}
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for _, sample := range inVec {
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// We are only looking for conventional buckets here. Remember
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// the histograms for later treatment.
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if sample.H != nil {
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histogramSamples = append(histogramSamples, sample)
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continue
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}
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upperBound, err := strconv.ParseFloat(
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el.Metric.Get(model.BucketLabel), 64,
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sample.Metric.Get(model.BucketLabel), 64,
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)
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if err != nil {
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// Oops, no bucket label or malformed label value. Skip.
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@ -924,30 +897,47 @@ func funcHistogramQuantile(vals []parser.Value, args parser.Expressions, enh *Ev
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continue
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}
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_, ok := enh.signatureToMetricWithHistograms[l]
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if ok {
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// This signature exists for both conventional and new
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// histograms, which is not supported.
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// TODO(beorn7): Issue a warning somehow.
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delete(enh.signatureToMetricWithBuckets, l)
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delete(enh.signatureToMetricWithHistograms, l)
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ignoreSignature[l] = true
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continue
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}
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l := sigf(sample.Metric)
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// Add the metric name (which is always removed) to the signature to prevent combining multiple histograms
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// with the same label set. See https://github.com/prometheus/prometheus/issues/9910
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l = l + el.Metric.Get(model.MetricNameLabel)
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// TODO(beorn7): What's the performance impact? We might need to implement this more efficiently.
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l = l + sample.Metric.Get(model.MetricNameLabel)
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mb, ok := enh.signatureToMetricWithBuckets[l]
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if !ok {
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el.Metric = labels.NewBuilder(el.Metric).
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sample.Metric = labels.NewBuilder(sample.Metric).
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Del(excludedLabels...).
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Labels()
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mb = &metricWithBuckets{el.Metric, nil}
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mb = &metricWithBuckets{sample.Metric, nil}
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enh.signatureToMetricWithBuckets[l] = mb
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}
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mb.buckets = append(mb.buckets, bucket{upperBound, el.V})
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mb.buckets = append(mb.buckets, bucket{upperBound, sample.V})
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}
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// Now deal with the histograms.
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for _, sample := range histogramSamples {
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// We have to reconstruct the exact same signature as above for
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// a conventional histogram, just ignoring any le label.
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// TODO(beorn7): This replicates the inefficient implementation
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// from above and has to be improved under the same
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// circumstances.
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l := string(sample.Metric.WithoutLabels().Bytes(enh.lblBuf))
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l = l + sample.Metric.Get(model.MetricNameLabel)
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if mb, ok := enh.signatureToMetricWithBuckets[l]; ok && len(mb.buckets) > 0 {
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// At this data point, we have conventional histogram
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// buckets and a native histogram with the same name and
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// labels. Do not evaluate anything.
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// TODO(beorn7): Issue a warning somehow.
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delete(enh.signatureToMetricWithBuckets, l)
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continue
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}
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enh.Out = append(enh.Out, Sample{
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Metric: enh.DropMetricName(sample.Metric),
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Point: Point{V: histogramQuantile(q, sample.H)},
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})
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}
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for _, mb := range enh.signatureToMetricWithBuckets {
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@ -959,15 +949,6 @@ func funcHistogramQuantile(vals []parser.Value, args parser.Expressions, enh *Ev
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}
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}
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for _, mh := range enh.signatureToMetricWithHistograms {
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if mh.histogram != nil {
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enh.Out = append(enh.Out, Sample{
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Metric: mh.metric,
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Point: Point{V: histogramQuantile(q, mh.histogram)},
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})
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}
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}
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return enh.Out
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}
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@ -47,11 +47,6 @@ type metricWithBuckets struct {
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buckets buckets
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}
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type metricWithHistograms struct {
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metric labels.Labels
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histogram *histogram.FloatHistogram
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}
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// bucketQuantile calculates the quantile 'q' based on the given buckets. The
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// buckets will be sorted by upperBound by this function (i.e. no sorting
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// needed before calling this function). The quantile value is interpolated
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