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Use binary literals for xor chunk encoding

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An opinionated cosmetic change, but since go 1.13 we have this fancy
0b.... literals so we don't need to write hex and comment the binary
value.

Signed-off-by: Oleg Zaytsev <mail@olegzaytsev.com>
This commit is contained in:
Oleg Zaytsev 2021-07-05 16:39:24 +02:00
parent 263847e64a
commit 40126a8494
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GPG key ID: 7E9FE9FD48F512EF
1 changed files with 9 additions and 9 deletions
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18
tsdb/chunkenc/xor.go
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@ -178,16 +178,16 @@ func (a *xorAppender) Append(t int64, v float64) {
case dod == 0: case dod == 0:
a.b.writeBit(zero) a.b.writeBit(zero)
case bitRange(dod, 14): case bitRange(dod, 14):
a.b.writeBits(0x02, 2) // '10' a.b.writeBits(0b10, 2)
a.b.writeBits(uint64(dod), 14) a.b.writeBits(uint64(dod), 14)
case bitRange(dod, 17): case bitRange(dod, 17):
a.b.writeBits(0x06, 3) // '110' a.b.writeBits(0b110, 3)
a.b.writeBits(uint64(dod), 17) a.b.writeBits(uint64(dod), 17)
case bitRange(dod, 20): case bitRange(dod, 20):
a.b.writeBits(0x0e, 4) // '1110' a.b.writeBits(0b1110, 4)
a.b.writeBits(uint64(dod), 20) a.b.writeBits(uint64(dod), 20)
default: default:
a.b.writeBits(0x0f, 4) // '1111' a.b.writeBits(0b1111, 4)
a.b.writeBits(uint64(dod), 64) a.b.writeBits(uint64(dod), 64)
} }
@ -344,15 +344,15 @@ func (it *xorIterator) Next() bool {
var sz uint8 var sz uint8
var dod int64 var dod int64
switch d { switch d {
case 0x00: case 0b0:
// dod == 0 // dod == 0
case 0x02: case 0b10:
sz = 14 sz = 14
case 0x06: case 0b110:
sz = 17 sz = 17
case 0x0e: case 0b1110:
sz = 20 sz = 20
case 0x0f: case 0b1111:
// Do not use fast because it's very unlikely it will succeed. // Do not use fast because it's very unlikely it will succeed.
bits, err := it.br.readBits(64) bits, err := it.br.readBits(64)
if err != nil { if err != nil {