Small improvement in handling cases without count

Signed-off-by: György Krajcsovits <gyorgy.krajcsovits@grafana.com>
This commit is contained in:
György Krajcsovits 2024-11-25 14:46:22 +01:00
parent 872e2db2a9
commit 41f051e9a4

View file

@ -139,19 +139,15 @@ func (h TempHistogram) Convert() (*histogram.Histogram, *histogram.FloatHistogra
return nil, nil, h.err
}
if len(h.buckets) == 0 || h.buckets[len(h.buckets)-1].le != math.Inf(1) {
// No +Inf bucket.
if !h.hasCount && len(h.buckets) > 0 {
// No count either, so set count to the last known bucket's count.
h.count = h.buckets[len(h.buckets)-1].count
}
// Let the last bucket be +Inf with the overall count.
h.buckets = append(h.buckets, tempHistogramBucket{le: math.Inf(1), count: h.count})
if !h.hasCount && len(h.buckets) > 0 {
// No count, so set count to the highest known bucket's count.
h.count = h.buckets[len(h.buckets)-1].count
}
if !h.hasCount {
h.count = h.buckets[len(h.buckets)-1].count
h.hasCount = true
if len(h.buckets) == 0 || h.buckets[len(h.buckets)-1].le != math.Inf(1) {
// No +Inf bucket.
// Let the last bucket be +Inf with the overall count.
h.buckets = append(h.buckets, tempHistogramBucket{le: math.Inf(1), count: h.count})
}
for _, b := range h.buckets {