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Rename bType to bName as Type returns the binary name and not the type name
See Parser.Type() function. Signed-off-by: György Krajcsovits <gyorgy.krajcsovits@grafana.com>
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@ -45,7 +45,7 @@ type NHCBParser struct {
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lset labels.Labels
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metricString string
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// For Type.
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bType []byte
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bName []byte
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typ model.MetricType
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// Caches the entry itself if we are inserting a converted NHCB
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@ -99,7 +99,7 @@ func (p *NHCBParser) Help() ([]byte, []byte) {
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}
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func (p *NHCBParser) Type() ([]byte, model.MetricType) {
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return p.bType, p.typ
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return p.bName, p.typ
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}
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func (p *NHCBParser) Unit() ([]byte, []byte) {
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@ -169,7 +169,7 @@ func (p *NHCBParser) Next() (Entry, error) {
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p.metricString = p.parser.Metric(&p.lset)
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p.lastNativeHistName = p.lset.Get(labels.MetricName)
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case EntryType:
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p.bType, p.typ = p.parser.Type()
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p.bName, p.typ = p.parser.Type()
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}
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if p.processNHCB() {
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p.entry = et
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@ -187,7 +187,7 @@ func (p *NHCBParser) handleClassicHistogramSeries(lset labels.Labels) bool {
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return false
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}
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mName := lset.Get(labels.MetricName)
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if convertnhcb.GetHistogramMetricBaseName(mName) != string(p.bType) {
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if convertnhcb.GetHistogramMetricBaseName(mName) != string(p.bName) {
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return false
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}
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switch {
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