promql: Clean up parser struct (#6360)

* promql: Clean up parser struct

The parser struct used two have two somewhat misused fields:

peekCount int
token     [3]item

By reading the code carefully one notices, that peekCount always has the value 0 or 1 and that only the first element of token is ever accessed.

To make this clearer, this commit replaces the token array with a single variable and the peekCount int with a boolean.

Signed-off-by: Tobias Guggenmos <tguggenm@redhat.com>
This commit is contained in:
Tobias Guggenmos 2019-11-25 12:29:14 +00:00 committed by Brian Brazil
parent 9497764011
commit c63259b83c

View file

@ -33,8 +33,8 @@ import (
type parser struct {
lex *lexer
token [3]item
peekCount int
token item
peeking bool
}
// ParseErr wraps a parsing error with line and position context.
@ -245,41 +245,42 @@ func (p *parser) typecheck(node Node) (err error) {
// next returns the next token.
func (p *parser) next() item {
if p.peekCount > 0 {
p.peekCount--
} else {
if !p.peeking {
t := p.lex.nextItem()
// Skip comments.
for t.typ == ItemComment {
t = p.lex.nextItem()
}
p.token[0] = t
p.token = t
}
if p.token[p.peekCount].typ == ItemError {
p.errorf("%s", p.token[p.peekCount].val)
p.peeking = false
if p.token.typ == ItemError {
p.errorf("%s", p.token.val)
}
return p.token[p.peekCount]
return p.token
}
// peek returns but does not consume the next token.
func (p *parser) peek() item {
if p.peekCount > 0 {
return p.token[p.peekCount-1]
if p.peeking {
return p.token
}
p.peekCount = 1
p.peeking = true
t := p.lex.nextItem()
// Skip comments.
for t.typ == ItemComment {
t = p.lex.nextItem()
}
p.token[0] = t
return p.token[0]
p.token = t
return p.token
}
// backup backs the input stream up one token.
func (p *parser) backup() {
p.peekCount++
p.peeking = true
}
// errorf formats the error and terminates processing.