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Fix issue where summation of +/- infinity returns NaN instead of infinity
Signed-off-by: Charles Korn <charles.korn@grafana.com>
This commit is contained in:
parent
c5040c5ea9
commit
fd6bdf5230
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@ -950,10 +950,14 @@ func funcTimestamp(vals []parser.Value, args parser.Expressions, enh *EvalNodeHe
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func kahanSumInc(inc, sum, c float64) (newSum, newC float64) {
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t := sum + inc
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switch {
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case math.IsInf(t, 0):
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c = 0
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// Using Neumaier improvement, swap if next term larger than sum.
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if math.Abs(sum) >= math.Abs(inc) {
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case math.Abs(sum) >= math.Abs(inc):
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c += (sum - t) + inc
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} else {
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default:
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c += (inc - t) + sum
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}
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return t, c
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81
promql/functions_internal_test.go
Normal file
81
promql/functions_internal_test.go
Normal file
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@ -0,0 +1,81 @@
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// Copyright 2015 The Prometheus Authors
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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// http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS,
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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package promql
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import (
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"fmt"
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"math"
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"testing"
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"github.com/stretchr/testify/require"
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)
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func TestKahanSumInc(t *testing.T) {
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testCases := map[string]struct {
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first float64
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second float64
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expected float64
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}{
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"+Inf + anything = +Inf": {
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first: math.Inf(1),
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second: 2.0,
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expected: math.Inf(1),
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},
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"-Inf + anything = -Inf": {
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first: math.Inf(-1),
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second: 2.0,
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expected: math.Inf(-1),
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},
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"+Inf + -Inf = NaN": {
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first: math.Inf(1),
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second: math.Inf(-1),
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expected: math.NaN(),
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},
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"NaN + anything = NaN": {
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first: math.NaN(),
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second: 2,
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expected: math.NaN(),
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},
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"NaN + Inf = NaN": {
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first: math.NaN(),
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second: math.Inf(1),
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expected: math.NaN(),
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},
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"NaN + -Inf = NaN": {
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first: math.NaN(),
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second: math.Inf(-1),
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expected: math.NaN(),
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},
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}
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runTest := func(t *testing.T, a, b, expected float64) {
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t.Run(fmt.Sprintf("%v + %v = %v", a, b, expected), func(t *testing.T) {
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sum, c := kahanSumInc(b, a, 0)
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result := sum + c
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if math.IsNaN(expected) {
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require.Truef(t, math.IsNaN(result), "expected result to be NaN, but got %v (from %v + %v)", result, sum, c)
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} else {
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require.Equalf(t, expected, result, "expected result to be %v, but got %v (from %v + %v)", expected, result, sum, c)
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}
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})
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}
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for name, testCase := range testCases {
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t.Run(name, func(t *testing.T) {
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runTest(t, testCase.first, testCase.second, testCase.expected)
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runTest(t, testCase.second, testCase.first, testCase.expected)
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})
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}
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}
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29
promql/promqltest/testdata/aggregators.test
vendored
29
promql/promqltest/testdata/aggregators.test
vendored
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@ -511,10 +511,39 @@ load 10s
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data{test="ten",point="b"} 8
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data{test="ten",point="c"} 1e+100
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data{test="ten",point="d"} -1e100
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data{test="pos_inf",group="1",point="a"} Inf
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data{test="pos_inf",group="1",point="b"} 2
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data{test="pos_inf",group="2",point="a"} 2
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data{test="pos_inf",group="2",point="b"} Inf
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data{test="neg_inf",group="1",point="a"} -Inf
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data{test="neg_inf",group="1",point="b"} 2
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data{test="neg_inf",group="2",point="a"} 2
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data{test="neg_inf",group="2",point="b"} -Inf
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data{test="inf_inf",point="a"} Inf
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data{test="inf_inf",point="b"} -Inf
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data{test="nan",group="1",point="a"} NaN
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data{test="nan",group="1",point="b"} 2
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data{test="nan",group="2",point="a"} 2
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data{test="nan",group="2",point="b"} NaN
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eval instant at 1m sum(data{test="ten"})
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{} 10
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eval instant at 1m sum by (group) (data{test="pos_inf"})
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{group="1"} Inf
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{group="2"} Inf
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eval instant at 1m sum by (group) (data{test="neg_inf"})
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{group="1"} -Inf
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{group="2"} -Inf
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eval instant at 1m sum(data{test="inf_inf"})
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{} NaN
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eval instant at 1m sum by (group) (data{test="nan"})
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{group="1"} NaN
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{group="2"} NaN
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clear
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# Test that aggregations are deterministic.
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@ -355,10 +355,10 @@ load 10m
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histogram_stddev_stdvar_7 {{schema:3 count:7 sum:Inf z_bucket:1 buckets:[0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 ] n_buckets:[0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 ]}}x1
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eval instant at 10m histogram_stddev(histogram_stddev_stdvar_7)
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{} NaN
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{} Inf
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eval instant at 10m histogram_stdvar(histogram_stddev_stdvar_7)
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{} NaN
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{} Inf
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# Apply quantile function to histogram with all positive buckets with zero bucket.
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load 10m
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