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c36961130b
This change is breaking, use the 'bool' modifier for such comprisons. After this change all comparisons without 'bool' will filter, and all comparisons with 'bool' will return 0/1. This makes the language more consistent and orthogonal, and ultimately easier to learn and use. If we ever figure out sane semantics for filtering scalar/scalar comparisons we can add them in, which will most likely come out of how the new vector() function is used.
48 lines
1.4 KiB
Plaintext
48 lines
1.4 KiB
Plaintext
load 5m
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http_requests{job="api-server", instance="0", group="production"} 0+10x10
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http_requests{job="api-server", instance="1", group="production"} 0+20x10
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http_requests{job="api-server", instance="0", group="canary"} 0+30x10
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http_requests{job="api-server", instance="1", group="canary"} 0+40x10
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http_requests{job="app-server", instance="0", group="production"} 0+50x10
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http_requests{job="app-server", instance="1", group="production"} 0+60x10
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http_requests{job="app-server", instance="0", group="canary"} 0+70x10
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http_requests{job="app-server", instance="1", group="canary"} 0+80x10
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eval instant at 50m SUM(http_requests) BY (job) > 1000
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{job="app-server"} 2600
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eval instant at 50m 1000 < SUM(http_requests) BY (job)
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{job="app-server"} 1000
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eval instant at 50m SUM(http_requests) BY (job) <= 1000
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{job="api-server"} 1000
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eval instant at 50m SUM(http_requests) BY (job) != 1000
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{job="app-server"} 2600
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eval instant at 50m SUM(http_requests) BY (job) == 1000
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{job="api-server"} 1000
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eval instant at 50m SUM(http_requests) BY (job) == bool 1000
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{job="api-server"} 1
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{job="app-server"} 0
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eval instant at 50m SUM(http_requests) BY (job) == bool SUM(http_requests) BY (job)
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{job="api-server"} 1
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{job="app-server"} 1
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eval instant at 50m SUM(http_requests) BY (job) != bool SUM(http_requests) BY (job)
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{job="api-server"} 0
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{job="app-server"} 0
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eval instant at 50m 0 == bool 1
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0
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eval instant at 50m 1 == bool 1
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1
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