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7ad36505d5
See also #11195 for the detailed reasoning. Signed-off-by: beorn7 <beorn@grafana.com> Signed-off-by: beorn7 <beorn@grafana.com>
233 lines
5.6 KiB
Go
233 lines
5.6 KiB
Go
// Copyright 2021 The Prometheus Authors
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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// http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS,
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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package chunkenc
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import (
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"math/bits"
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"github.com/pkg/errors"
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)
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// putVarbitInt writes an int64 using varbit encoding with a bit bucketing
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// optimized for the dod's observed in histogram buckets, plus a few additional
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// buckets for large numbers.
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//
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// For optimal space utilization, each branch didn't need to support any values
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// of any of the prior branches. So we could expand the range of each branch. Do
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// more with fewer bits. It would come at the price of more expensive encoding
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// and decoding (cutting out and later adding back that center-piece we
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// skip). With the distributions of values we see in practice, we would reduce
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// the size by around 1%. A more detailed study would be needed for precise
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// values, but it's appears quite certain that we would end up far below 10%,
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// which would maybe convince us to invest the increased coding/decoding cost.
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func putVarbitInt(b *bstream, val int64) {
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switch {
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case val == 0: // Precisely 0, needs 1 bit.
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b.writeBit(zero)
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case bitRange(val, 3): // -3 <= val <= 4, needs 5 bits.
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b.writeBits(0b10, 2)
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b.writeBits(uint64(val), 3)
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case bitRange(val, 6): // -31 <= val <= 32, 9 bits.
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b.writeBits(0b110, 3)
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b.writeBits(uint64(val), 6)
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case bitRange(val, 9): // -255 <= val <= 256, 13 bits.
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b.writeBits(0b1110, 4)
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b.writeBits(uint64(val), 9)
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case bitRange(val, 12): // -2047 <= val <= 2048, 17 bits.
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b.writeBits(0b11110, 5)
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b.writeBits(uint64(val), 12)
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case bitRange(val, 18): // -131071 <= val <= 131072, 3 bytes.
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b.writeBits(0b111110, 6)
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b.writeBits(uint64(val), 18)
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case bitRange(val, 25): // -16777215 <= val <= 16777216, 4 bytes.
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b.writeBits(0b1111110, 7)
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b.writeBits(uint64(val), 25)
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case bitRange(val, 56): // -36028797018963967 <= val <= 36028797018963968, 8 bytes.
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b.writeBits(0b11111110, 8)
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b.writeBits(uint64(val), 56)
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default:
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b.writeBits(0b11111111, 8) // Worst case, needs 9 bytes.
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b.writeBits(uint64(val), 64)
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}
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}
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// readVarbitInt reads an int64 encoced with putVarbitInt.
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func readVarbitInt(b *bstreamReader) (int64, error) {
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var d byte
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for i := 0; i < 8; i++ {
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d <<= 1
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bit, err := b.readBitFast()
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if err != nil {
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bit, err = b.readBit()
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}
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if err != nil {
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return 0, err
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}
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if bit == zero {
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break
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}
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d |= 1
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}
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var val int64
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var sz uint8
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switch d {
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case 0b0:
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// val == 0
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case 0b10:
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sz = 3
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case 0b110:
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sz = 6
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case 0b1110:
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sz = 9
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case 0b11110:
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sz = 12
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case 0b111110:
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sz = 18
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case 0b1111110:
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sz = 25
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case 0b11111110:
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sz = 56
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case 0b11111111:
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// Do not use fast because it's very unlikely it will succeed.
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bits, err := b.readBits(64)
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if err != nil {
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return 0, err
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}
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val = int64(bits)
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default:
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return 0, errors.Errorf("invalid bit pattern %b", d)
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}
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if sz != 0 {
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bits, err := b.readBitsFast(sz)
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if err != nil {
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bits, err = b.readBits(sz)
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}
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if err != nil {
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return 0, err
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}
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if bits > (1 << (sz - 1)) {
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// Or something.
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bits = bits - (1 << sz)
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}
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val = int64(bits)
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}
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return val, nil
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}
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func bitRangeUint(x uint64, nbits int) bool {
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return bits.LeadingZeros64(x) >= 64-nbits
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}
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// putVarbitUint writes a uint64 using varbit encoding. It uses the same bit
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// buckets as putVarbitInt.
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func putVarbitUint(b *bstream, val uint64) {
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switch {
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case val == 0: // Precisely 0, needs 1 bit.
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b.writeBit(zero)
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case bitRangeUint(val, 3): // val <= 7, needs 5 bits.
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b.writeBits(0b10, 2)
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b.writeBits(val, 3)
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case bitRangeUint(val, 6): // val <= 63, 9 bits.
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b.writeBits(0b110, 3)
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b.writeBits(val, 6)
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case bitRangeUint(val, 9): // val <= 511, 13 bits.
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b.writeBits(0b1110, 4)
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b.writeBits(val, 9)
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case bitRangeUint(val, 12): // val <= 4095, 17 bits.
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b.writeBits(0b11110, 5)
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b.writeBits(val, 12)
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case bitRangeUint(val, 18): // val <= 262143, 3 bytes.
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b.writeBits(0b111110, 6)
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b.writeBits(val, 18)
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case bitRangeUint(val, 25): // val <= 33554431, 4 bytes.
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b.writeBits(0b1111110, 7)
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b.writeBits(val, 25)
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case bitRangeUint(val, 56): // val <= 72057594037927935, 8 bytes.
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b.writeBits(0b11111110, 8)
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b.writeBits(val, 56)
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default:
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b.writeBits(0b11111111, 8) // Worst case, needs 9 bytes.
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b.writeBits(val, 64)
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}
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}
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// readVarbitUint reads a uint64 encoced with putVarbitUint.
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func readVarbitUint(b *bstreamReader) (uint64, error) {
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var d byte
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for i := 0; i < 8; i++ {
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d <<= 1
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bit, err := b.readBitFast()
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if err != nil {
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bit, err = b.readBit()
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}
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if err != nil {
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return 0, err
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}
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if bit == zero {
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break
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}
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d |= 1
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}
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var (
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bits uint64
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sz uint8
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err error
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)
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switch d {
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case 0b0:
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// val == 0
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case 0b10:
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sz = 3
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case 0b110:
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sz = 6
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case 0b1110:
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sz = 9
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case 0b11110:
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sz = 12
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case 0b111110:
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sz = 18
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case 0b1111110:
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sz = 25
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case 0b11111110:
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sz = 56
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case 0b11111111:
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// Do not use fast because it's very unlikely it will succeed.
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bits, err = b.readBits(64)
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if err != nil {
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return 0, err
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}
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default:
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return 0, errors.Errorf("invalid bit pattern %b", d)
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}
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if sz != 0 {
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bits, err = b.readBitsFast(sz)
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if err != nil {
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bits, err = b.readBits(sz)
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}
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if err != nil {
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return 0, err
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}
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}
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return bits, nil
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}
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