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b866db009b
There was a subtle and nasty bug in listSeriesIterator.Seek. In addition, the Seek call is defined to be a no-op if the current position of the iterator is already pointing to a suitable sample. This commit adds fast paths for this case to several potentially expensive Seek calls. Another bug was in concreteSeriesIterator.Seek. It always searched the whole series and not from the current position of the iterator. Signed-off-by: beorn7 <beorn@grafana.com>
55 lines
1.5 KiB
Go
55 lines
1.5 KiB
Go
// Copyright 2021 The Prometheus Authors
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// Licensed under the Apache License, Version 2.0 (the "License");
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// you may not use this file except in compliance with the License.
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// You may obtain a copy of the License at
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//
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// http://www.apache.org/licenses/LICENSE-2.0
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//
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// Unless required by applicable law or agreed to in writing, software
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// distributed under the License is distributed on an "AS IS" BASIS,
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// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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// See the License for the specific language governing permissions and
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// limitations under the License.
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package storage
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import (
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"testing"
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"github.com/stretchr/testify/require"
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)
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func TestListSeriesIterator(t *testing.T) {
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it := NewListSeriesIterator(samples{sample{0, 0}, sample{1, 1}, sample{1, 1.5}, sample{2, 2}, sample{3, 3}})
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// Seek to the first sample with ts=1.
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require.True(t, it.Seek(1))
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ts, v := it.At()
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require.Equal(t, int64(1), ts)
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require.Equal(t, 1., v)
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// Seek one further, next sample still has ts=1.
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require.True(t, it.Next())
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ts, v = it.At()
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require.Equal(t, int64(1), ts)
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require.Equal(t, 1.5, v)
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// Seek again to 1 and make sure we stay where we are.
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require.True(t, it.Seek(1))
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ts, v = it.At()
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require.Equal(t, int64(1), ts)
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require.Equal(t, 1.5, v)
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// Another seek.
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require.True(t, it.Seek(3))
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ts, v = it.At()
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require.Equal(t, int64(3), ts)
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require.Equal(t, 3., v)
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// And we don't go back.
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require.True(t, it.Seek(2))
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ts, v = it.At()
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require.Equal(t, int64(3), ts)
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require.Equal(t, 3., v)
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}
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